Adscend

Click Here



Click Here



Click Here
Showing posts with label Broadcast Valid Host Range Class B. Show all posts
Showing posts with label Broadcast Valid Host Range Class B. Show all posts

5.9.13

Broadcast Valid Host Range Class C

Subnet, Broadcast, Valid Host Range:Class C


Example: 1
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.0 255.255.255.128(/25).

Example: 2
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.0 255.255.255.192(/26).

Example: 3
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.0 255.255.255.224(/27).

Example: 4
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.0 255.255.255.240(/28).

Example: 5
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.0 255.255.255.248(/29).

Example: 6
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.0 255.255.255.252(/30).

Example: 7
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.68 255.255.255.192.

Example: 8
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.65 255.255.255.224.

Example: 9
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.38 255.255.255.240.

Example: 10
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.26 255.255.255.248.

Example: 11
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.13 255.255.255.252.

Example: 12
Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.99 255.255.255.248.

Example: 13
192.168.100.17 255.255.255.248(/29)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?

Example: 14
192.168.100.25 255.255.255.252
What is the valid subnet?
What is the broadcast address?
What is the valid host range?

Example: 15
192.168.100.37 255.255.255.240(/28)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?

Example: 16
192.168.100.37 255.255.255.248(/29)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?

Example: 17
192.168.100.66 255.255.255.224(/27)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?

Example: 18
192.168.100.99 255.255.255.128(/25)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?

Example: 19
192.168.100.99 255.255.255.192(/26)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?


Example 1: Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.0 255.255.255.128(/25).
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.128
                  = 255. 255. 255. 10000000
Subnets = 2^1 = 2.
Hosts = 2^7 – 2 = 126.
Block Size = 2^7 = 128.
Valid subnets = 256 – 128 = 128, means we have a block size of
128 in the forth octet.
Subnets are 0, 128.
Address 0 falls in the 0 subnet.
Subnet = 192. 168. 10. 0
The subnets would be 192.168.10.0, 192.168.10.128.
 
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.126 192.168.10.127
192.168.10.128 192.168.10.129-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.0.
The broadcast address is: 192.168.10.127.
The valid host range: 192.168.10.1-192.168.10.126.

Example 2: Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.0 255.255.255.192(/26).
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.192
                  = 255. 255. 255. 11000000
Subnets = 2^2 = 4.
Hosts = 2^6 – 2 = 62.
Block Size = 2^6 = 64.
Valid subnets = 256 – 192 = 64, means we have a block size of
64 in the forth octet.
Subnets are 0, 64, 128, 192.
Address 0 falls in the 0 subnet.
Subnet = 192. 168. 10. 0
The subnets would be 192.168.10.0, 192.168.10.64, 192.168.10.128,
192.168.10.192.
 
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.62 192.168.10.63
192.168.10.64 192.168.10.65-192.168.10.126 192.168.10.127
192.168.10.128 192.168.10.129-192.168.10.190 192.168.10.191
192.168.10.192 192.168.10.193-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.0.
The broadcast address is: 192.168.10.63.
The valid host range: 192.168.10.1-192.168.10.62.

Example 3: Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.0 255.255.255.224(/27).
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.224
                  = 255. 255. 255. 11100000
Subnets = 2^3 = 8.
Hosts = 2^5 – 2 = 30.
Block Size =2^5 = 32.
Valid subnets = 256 – 224 = 32, means we have a block size of
32 in the forth octet.
Subnets are 0, 32, 64, 96, 128, 160, 192, 224.
Address 0 falls in the 0 subnet.
Subnet = 192. 168. 10. 0
The subnets would be 192.168.10.0, 192.168.10.32, 192.168.10.64,
192.168.10.96, 192.168.10.128, 192.168.10.160, 192.168.10.192,
192.168.10.224.
 
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.30 192.168.10.31
192.168.10.32 192.168.10.33-192.168.10.62 192.168.10.63
192.168.10.64 192.168.10.65-192.168.10.94 192.168.10.95
192.168.10.96 192.168.10.97-192.168.10.126 192.168.10.127
192.168.10.128 192.168.10.129-192.168.10.158 192.168.10.159
192.168.10.160 192.168.10.161-192.168.10.190 192.168.10.191
192.168.10.192 192.168.10.193-192.168.10.222 192.168.10.223
192.168.10.224 192.168.10.225-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.0.
The broadcast address is: 192.168.10.31.
The valid host range: 192.168.10.1-192.168.10.30.

Example 4: Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.248.0(/21).
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.240
                  = 255. 255. 255. 11110000
Subnets = 2^4 = 16.
Hosts = 2^4 – 2 = 14.
Block Size = 2^4 = 16.
Valid subnets = 256 – 240 = 16, means we have a block size of
16 in the forth octet.
Subnets are 0, 16, 32, 48, 64, 80, … , 240.
Address 0 falls in the 0 subnet.
Subnet = 192. 168. 10. 0
The subnets would be 192.168.10.0, 192.168.10.16, 192.168.10.32,
192.168.10.48, 192.168.10.64, 192.168.10.80, … , 192.168.10.240.
 
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.14 192.168.10.15
192.168.10.16 192.168.10.17-192.168.10.30 192.168.10.31
192.168.10.32 192.168.10.33-192.168.10.46 192.168.10.47
192.168.10.48 192.168.10.49-192.168.10.62 192.168.10.63
192.168.10.64 192.168.10.65-192.168.10.78 192.168.10.79
192.168.10.80 192.168.10.81-192.168.10.94 192.168.10.95
. . .
192.168.10.240 192.168.10.241-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.0.
The broadcast address is: 192.168.10.15.
The valid host range: 192.168.10.1-192.168.10.14.

Example 5: Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.0 255.255.255.248(/29).
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.248
                  = 255. 255. 255. 11111000
Subnets = 2^5 = 32.
Hosts = 2^3 – 2 = 8.
Block Size = 2^3 = 8.
Valid subnets = 256 – 248 = 8, means we have a block size of
8 in the forth octet.
Subnets are 0, 8, 16, 24, 32, 40, … , 248.
Address 0 falls in the 0 subnet.
Subnet = 192. 168. 10. 0
The subnets would be 192.168.10.0, 192.168.10.8, 192.168.10.16,
192.168.10.24, 192.168.10.32, 192.168.10.40, … , 192.168.10.248.
 
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.6 192.168.10.7
192.168.10.8 192.168.10.9-192.168.10.14 192.168.10.15
192.168.10.16 192.168.10.17-192.168.10.22 192.168.10.23
192.168.10.24 192.168.10.25-192.168.10.30 192.168.10.31
192.168.10.32 192.168.10.33-192.168.10.38 192.168.10.39
192.168.10.40 192.168.10.41-192.168.10.46 192.168.10.47
. . .
192.168.10.240 192.168.10.241-192.168.10.246 192.168.10.247
192.168.10.248 192.168.10.249-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.0.
The broadcast address is: 192.168.10.7.
The valid host range: 192.168.10.1-192.168.10.6.

Example 6: Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.0 255.255.255.252(/30).
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.252
                  = 255. 255. 255. 11111100
Subnets = 2^6 = 64.
Hosts = 2^2 – 2 = 2.
Block Size = 2^2 = 4.
Valid subnets = 256 – 252 = 4, means we have a block size of
4 in the forth octet.
Subnets are 0, 4, 8, 12, 16, … , 248, 252.
Address 0 falls in the 0 subnet.
Subnet = 192. 168. 10. 0
The subnets would be 192.168.10.0, 192.168.10.4, 192.168.10.8,
192.168.10.12, 192.168.10.16, … , 192.168.10.248, 192.168.10.252.
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.2 192.168.10.3
192.168.10.4 192.168.10.5-192.168.10.6 192.168.10.7
192.168.10.8 192.168.10.9-192.168.10.10 192.168.10.11
192.168.10.12 192.168.10.13-192.168.10.14 192.168.10.15
192.168.10.16 192.168.10.17-192.168.10.18 192.168.10.19
. . .
192.168.10.248 192.168.10.249-192.168.10.250 192.168.10.251
192.168.10.252 192.168.10.253-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.0.
The broadcast address is:192.168.10.3.
The valid host range: 192.168.10.1-192.168.10.2.

Example 7: Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.68 255.255.255.192.
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.192
                  = 255. 255. 255. 11000000
Subnets = 2^2 = 4.
Hosts = 2^6 – 2 = 62.
Block Size = 2^6 = 4.
Valid subnets = 256 – 192 = 64, means we have a block size of
64 in the forth octet.
Subnets are 0, 64, 128, 192.
Address 68 falls in the 64 subnet.
Subnet = 192. 168. 10. 64
The subnets would be 192.168.10.0, 192.168.10.64, 192.168.10.128,
192.168.10.192.
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.62 192.168.10.63
192.168.10.64 192.168.10.65-192.168.10.126 192.168.10.127
192.168.10.128 192.168.10.129-192.168.10.190 192.168.10.191
192.168.10.192 192.168.10.193-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.64.
The broadcast address is: 192.168.10.127.
The valid host range: 192.168.10.65-192.168.10.126.

Example 8: Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.65 255.255.255.224.
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.224
                  = 255. 255. 255. 11100000
Subnets = 2^3 = 8.
Hosts = 2^5 – 2 = 30.
Block Size = 2^5 = 32.
Valid subnets = 256 – 224 = 32, means we have a block size of
32 in the forth octet.
Subnets are 0, 32, 64, 96, … , 224.
Address 65 falls in the 64 subnet.
Subnet = 192. 168. 10. 64
The subnets would be 192.168.10.0, 192.168.10.32, 192.168.10.64,
192.168.10.96, … ,192.168.10.224.
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.30 192.168.10.31
192.168.10.32 192.168.10.33-192.168.10.62 192.168.10.63
192.168.10.64 192.168.10.65-192.168.10.94 192.168.10.95
192.168.10.96 192.168.10.97-192.168.10.126 192.168.10.127
. . .
192.168.10.224 192.168.10.225-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.64.
The broadcast address is: 192.168.10.95.
The valid host range: 192.168.10.65-192.168.10.94.

Example 9: Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.38 255.255.255.240.
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.240
                  = 255. 255. 255. 11110000
Subnets = 2^ = 16.
Hosts = 2^4 – 2 = 14.
Block Size = 2^5 = 32.
Valid subnets = 256 – 224 = 16, means we have a block size of
16 in the forth octet.
Subnets are 0, 16, 32, 48, … , 240.
Address 38 falls in the 32 subnet.
Subnet = 192. 168. 10. 32
The subnets would be 192.168.10.0, 192.168.10.16, 192.168.10.32,
192.168.10.48, … ,192.168.10.240.
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.14 192.168.10.15
192.168.10.16 192.168.10.17-192.168.10.30 192.168.10.31
192.168.10.32 192.168.10.33-192.168.10.46 192.168.10.47
192.168.10.48 192.168.10.49-192.168.10.62 192.168.10.63
. . .
192.168.10.240 192.168.10.241-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.32.
The broadcast address is: 192.168.10.47.
The valid host range: 192.168.10.33-192.168.10.46.

Example 10: Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.26 255.255.255.248.
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.248
                  = 255. 255. 255. 11111000
Subnets = 2^5 = 32.
Hosts = 2^3 – 2 = 6.
Block Size = 2^3 = 8.
Valid subnets = 256 – 248 = 8, means we have a block size of
8 in the forth octet.
Subnets are 0, 8, 16, 24, 32, … , 248.
Address 26 falls in the 24 subnet.
Subnet = 192. 168. 10. 24
The subnets would be 192.168.10.0, 192.168.10.8, 192.168.10.16,
192.168.10.24, … ,192.168.10.248.
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.6 192.168.10.7
192.168.10.8 192.168.10.9-192.168.10.14 192.168.10.15
192.168.10.16 192.168.10.17-192.168.10.22 192.168.10.23
192.168.10.24 192.168.10.25-192.168.10.30 192.168.10.31
. . .
192.168.10.248 192.168.10.249-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.24.
The broadcast address is: 192.168.10.31.
The valid host range: 192.168.10.25-192.168.10.30.

Example 11: Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.13 255.255.255.252.
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.252
                  = 255. 255. 255. 11111100
Subnets = 2^6 = 64.
Hosts = 2^2 – 2 = 2.
Block Size = 2^2 = 4.
Valid subnets = 256 – 252 = 4, means we have a block size of
4 in the forth octet.
Subnets are 0, 4, 8, 12, 16, … , 252.
Address 13 falls in the 12 subnet.
Subnet = 192. 168. 10. 12
The subnets would be 192.168.10.0, 192.168.10.8, 192.168.10.12,
192.168.10.16, … ,192.168.10.252.
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.2 192.168.10.3
192.168.10.4 192.168.10.5-192.168.10.6 192.168.10.7
192.168.10.8 192.168.10.9-192.168.10.10 192.168.10.11
192.168.10.12 192.168.10.13-192.168.10.14 192.168.10.15
192.168.10.16 192.168.10.17-192.168.10.18 192.168.10.19
. . .
. . .
192.168.10.252 192.168.10.253-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.12.
The broadcast address is: 192.168.10.15.
The valid host range: 192.168.10.13-192.168.10.14.

Example 12: Calculate Subnet, Broadcast, Valid Host Range of 192.168.10.99 255.255.255.248.
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.248
                  = 255. 255. 255. 11111000
Subnets = 2^5 = 32.
Hosts = 2^3 – 2 = 6.
Block Size = 2^3 = 8.
Valid subnets = 256 – 248 = 8, means we have a block size of
8 in the forth octet.
Subnets are 0, 8, 16, 24, 32, … , 88, 96, 248.
Address 99 falls in the 96 subnet.
Subnet = 192. 168. 10. 96
The subnets would be 192.168.10.0, 192.168.10.8, 192.168.10.16,
192.168.10.24, 192.168.10.24,
…, 192.168.10.248.
Network Assignable Host Broadcast
192.168.10.0 192.168.10.1-192.168.10.6 192.168.10.7
192.168.10.8 192.168.10.9-192.168.10.14 192.168.10.15
192.168.10.16 192.168.10.17-192.168.10.22 192.168.10.23
192.168.10.24 192.168.10.25-192.168.10.30 192.168.10.31
192.168.10.32 192.168.10.33-192.168.10.38 192.168.10.39
. . .
. . .
192.168.10.88 192.168.10.89-192.168.10.94 192.168.10.95
192.168.10.96 192.168.10.97-192.168.10.102 192.168.10.103
. . .
. . .
192.168.10.248 192.168.10.249-192.168.10.254 192.168.10.255
The subnet is: 192.168.10.96.
The broadcast address is: 192.168.10.103.
The valid host range: 192.168.10.97-192.168.10.102.

Example 13: 192.168.100.17 255.255.255.248(/29)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.248
                  = 255. 255. 255. 11111000
Subnets = 2^5 = 32.
Hosts = 2^3 – 2 = 6.
Block Size = 2^3 = 8.
Valid subnets = 256 – 248 = 8, means we have a block size of
8 in the forth octet.
Subnets are 0, 8, 16, 24, 32, … , 88, 96, 248.
Address 17 falls in the 16 subnet.
Subnet = 192. 168. 100. 16
The subnets would be 192.168.100.0, 192.168.100.8, 192.168.100.16,
192.168.100.24, …, 192.168.100.248.
Network Assignable Host Broadcast
192.168.100.0 192.168.100.1-192.168.100.6 192.168.100.7
192.168.100.8 192.168.100.9-192.168.100.14 192.168.100.15
192.168.100.16 192.168.100.17-192.168.100.22 192.168.100.23
192.168.100.24 192.168.100.25-192.168.100.30 192.168.100.31
. . .
. . .
192.168.100.248 192.168.100.249-192.168.100.254 192.168.100.255
The subnet is: 192.168.100.16.
The broadcast address is: 192.168.100.23.
The valid host range: 192.168.100.17-192.168.100.22.

Example 14: 192.168.100.25 255.255.255.252
What is the valid subnet?
What is the broadcast address?
What is the valid host range?
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.252
                  = 255. 255. 255. 11111100
Subnets = 2^6 = 64.
Hosts = 2^2 – 2 = 2.
Block Size = 2^2 = 4.
Valid subnets = 256 – 252 = 4, means we have a block size of
4 in the forth octet.
Subnets are 0, 4, 8, 12, 16, 20, 24, 28, … 252.
Address 25 falls in the 24 subnet.
Subnet = 192. 168. 100. 24
The subnets would be 192.168.100.0, 192.168.100.4, 192.168.100.8,
192.168.100.12, 192.168.100.16, 192.168.100.20, 192.168.100.24,
192.168.100.28 ,…, 192.168.100.252.
Network Assignable Host Broadcast
192.168.100.0 192.168.100.1-192.168.100.2 192.168.100.3
192.168.100.4 192.168.100.5-192.168.100.6 192.168.100.7
192.168.100.8 192.168.100.9-192.168.100.10 192.168.100.11
192.168.100.12 192.168.100.13-192.168.100.14 192.168.100.15
192.168.100.16 192.168.100.17-192.168.100.18 192.168.100.19
192.168.100.20 192.168.100.21-192.168.100.22 192.168.100.23
192.168.100.24 192.168.100.25-192.168.100.26 192.168.100.27
192.168.100.28 192.168.100.29-192.168.100.30 192.168.100.31
. . .
. . .
192.168.100.252 192.168.100.253-192.168.100.254 192.168.100.255
The subnet is: 192.168.100.24.
The broadcast address is: 192.168.100.27.
The valid host range: 192.168.100.25-192.168.100.26.

Example 15: 192.168.100.37 255.255.255.240(/28)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.240
                  = 255. 255. 255. 11110000
Subnets = 2^4 = 16.
Hosts = 2^4 – 2 = 14.
Block Size = 2^4 = 16.
Valid subnets = 256 – 240 = 16, means we have a block size of
16 in the forth octet.
Subnets are 0, 16, 32, 48, … 240.
Address 37 falls in the 32 subnet.
Subnet = 192. 168. 100. 32
The subnets would be 192.168.100.0, 192.168.100.16,
192.168.100.32, 192.168.100.48, …, 192.168.100.240.
Network Assignable Host Broadcast
192.168.100.0 192.168.100.1-192.168.100.14 192.168.100.15
192.168.100.16 192.168.100.17-192.168.100.30 192.168.100.31
192.168.100.32 192.168.100.33-192.168.100.46 192.168.100.47
192.168.100.48 192.168.100.49-192.168.100.62 192.168.100.63
. . .
. . .
192.168.100.240 192.168.100.241-192.168.100.254 192.168.100.255
The subnet is: 192.168.100.32.
The broadcast address is: 192.168.100.47.
The valid host range: 192.168.100.33-192.168.100.46.

Example 16: 192.168.100.37 255.255.255.248(/29)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.248
                  = 255. 255. 255. 11111000
Subnets = 2^5 = 32.
Hosts = 2^3 – 2 = 6.
Block Size = 2^3 = 8.
Valid subnets = 256 – 248 = 8, means we have a block size of
8 in the forth octet.
Subnets are 0, 8, 16, 24, 32, 40, 48, … 248.
Address 37 falls in the 32 subnet.
Subnet = 192. 168. 100. 32
The subnets would be 192.168.100.0, 192.168.100.8, 192.168.100.16,
192.168.100.24, 192.168.100.32, 192.168.100.40, 192.168.100.48, … ,
192.168.100.248.
Network Assignable Host Broadcast
192.168.100.0 192.168.100.1-192.168.100.6 192.168.100.7
192.168.100.8 192.168.100.9-192.168.100.14 192.168.100.15
192.168.100.16 192.168.100.17-192.168.100.22 192.168.100.23
192.168.100.24 192.168.100.25-192.168.100.30 192.168.100.31
92.168.100.32 192.168.100.33-192.168.100.38 192.168.100.39
192.168.100.40 192.168.100.41-192.168.100.46 192.168.100.47
192.168.100.48 192.168.100.49-192.168.100.54 192.168.100.55
. . .
192.168.100.248 192.168.100.249-192.168.100.254 192.168.100.255
The subnet is: 192.168.100.32.
The broadcast address is: 192.168.100.39.
The valid host range: 192.168.100.33-192.168.100.38.

Example 17: 192.168.100.66 255.255.255.224(/27)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.224
                  = 255. 255. 255. 11100000
Subnets = 2^3 = 8.
Hosts = 2^5 – 2 = 30.
Block Size = 2^5 = 32.
Valid subnets = 256 – 224 = 32, means we have a block size of
32 in the forth octet.
Subnets are 0, 32, 64, 96, … 224.
Address 66 falls in the 64 subnet.
Subnet = 192. 168. 100. 32
The subnets would be 192.168.100.0, 192.168.100.32,192.168.100.64,
192.168.100.96, …, 192.168.100.224.
Network Assignable Host Broadcast
192.168.100.0 192.168.100.1-192.168.100.30 192.168.100.31
192.168.100.32 192.168.100.33-192.168.100.62 192.168.100.63
192.168.100.64 192.168.100.65-192.168.100.94 192.168.100.95
192.168.100.96 192.168.100.97-192.168.100.126 192.168.100.127
. . .
. . .
192.168.100.224 192.168.100.225-192.168.100.254 192.168.100.255
The subnet is: 192.168.100.64.
The broadcast address is: 192.168.100.95.
The valid host range: 192.168.100.65-192.168.100.94.

Example 18: 192.168.100.99 255.255.255.128(/25)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.128
                  = 255. 255. 255. 10000000
Subnets = 2^1 = 2.
Hosts = 2^7 – 2 = 126.
Block Size = 2^7 = 128.
Valid subnets = 256 – 128 = 128, means we have a block size of
128 in the forth octet.
Subnets are 0, 128.
Address 99 falls in the 0 subnet.
Subnet = 192. 168. 100. 0
The subnets would be 192.168.100.0, 192.168.100.128.
Network Assignable Host Broadcast
192.168.100.0 192.168.100.1-192.168.100.126 192.168.100.127
192.168.100.128 192.168.100.129-192.168.100.254 192.168.100.255
The subnet is: 192.168.100.0.
The broadcast address is: 192.168.100.127.
The valid host range: 192.168.100.1-192.168.100.126.

Example 19: 192.168.100.99 255.255.255.192(/26)
What is the valid subnet?
What is the broadcast address?
What is the valid host range?
Solution
Class C addresses use a default mask of 255.255.255.0.
Given subnet mask = 255.255.255.192
                  = 255. 255. 255. 11000000
Subnets = 2^2 =4.
Hosts = 2^6 – 2 = 62.
Block Size = 2^6 = 64.
Valid subnets = 256 – 192 = 64, means we have a block size of
64 in the forth octet.
Subnets are 0, 64, 128, 192.
Address 99 falls in the 64 subnet.
Subnet = 192. 168. 100. 64
The subnets would be 192.168.100.0, 192.168.100.64,
192.168.100.128, 192.168.100.192.
Network Assignable Host Broadcast
192.168.100.0 192.168.100.1-192.168.100.62 192.168.100.63
192.168.100.64 192.168.100.65-192.168.100.126 192.168.100.127
192.168.100.128 192.168.100.129-192.168.100.190 192.168.100.191
192.168.100.192 192.168.100.193-192.168.100.254 192.168.100.255
The subnet is: 192.168.100.64.
The broadcast address is: 192.168.100.127.
The valid host range: 192.168.100.65-192.168.100.126.