Subnet Tutorials: Only Number Of Host

Only Number Of Host

Class B

Example 1:

You are given a Class B network with a subnet mask of 255.255.255.192. How many host addresses are there on each subnet?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.255.192
 		  = 255. 255. 11111111. 11000000
Host bits = 6 or 6 bits available for host addresses.
Hosts = 2^6 – 2 = 62.
Number of hosts possible = 62.

Example 2:

For the subnet mask 255.255.192.0, how many hosts per subnet are possible?

Solution:

Solution:
Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.192.0
                  = 255. 255. 11000000. 00000000
Host bits = 14 or 14 bits available for host addresses.
Hosts = 2^14 - 2 = 16382.
Number of hosts possible = 16382.

Class c

Example 3:

You are given a Class C network with a subnet mask of 255.255.255.248.How many host addresses are there on each subnet?

Solution:

Class C addresses use a default mask of 255.255.255.0
Given subnet mask = 255.255.255.248
                  = 255. 255. 255.11111000
Host bits = 3 or 3 bits available for host addresses.
Hosts = 2^3 – 2 = 6.
Number of hosts possible = 6.

Calculating Number of Hosts And Subnets
Class B

Example 4:

How many subnets and hosts per subnet can you get from the network 172.16.0.0/23?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.254.0 = /23
                  = 255. 255. 11111110. 00000000
Subnet Bits = 7,corresponds to 2^7 = 128 subnets.
Host Bits = 9,corresponds to (2^9-2) = 510 hosts.
128 subnets and 510 hosts.

Example 5:

How many subnets and hosts per subnet can you get from the network 172.18.0.0/20?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.240.0 = /20
                  = 255. 255. 11110000. 00000000
Subnet Bits = 4, corresponds to 2^4 = 16 subnets.
Host Bits = 12 , corresponds to (2^12-2) = 4094 hosts.
16 subnets and 4094 hosts.

Example 6:

How many subnets and hosts per subnet can you get from the network 172.19.0.0/26?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.255.192 = /26
                  = 255. 255. 11111111. 11000000
Subnet Bits = 10 , corresponds to 2^10 = 1024 subnets.
Host Bits = 6 , corresponds to (2^6-2) = 62 hosts.
1024 subnets and 62 hosts.

Example 7:

How many subnets and hosts per subnet can you get from the network 172.20.0.0/23?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.254.0 = /23
                  = 255. 255. 11111110. 00000000
Subnet Bits = 7 , corresponds to 2^7 = 128 subnets.
Host Bits = 9 , corresponds to (2^9-2) = 510 hosts.
128 subnets and 510 hosts.

Example 8:

How many subnets and hosts per subnet can you get from the network 172.20.0.0 255.255.255.240?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.255.240 = /28
                  = 255. 255. 11111111. 11110000
Subnet Bits = 12 , corresponds to 2^12 = 4096 subnets.
Host Bits = 4 , corresponds to (2^4-2) = 14 hosts.
4096 subnets and 14 hosts.

Example 9:

How many subnets and hosts per subnet can you get from the network 172.21.0.0 255.255.252.0?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.252.0 = /22
                  = 255. 255. 11111100. 00000000
Subnet Bits = 6, corresponds to 2^6 = 64 subnets.
Host Bits = 10, corresponds to (2^10-2) = 1022 hosts.
64 subnets and 1022 hosts.

Example 10:

How many subnets and hosts per subnet can you get from the network 172.22.0.0/28?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.255.240 = /28
                  = 255. 255. 11111111. 11110000
Subnet Bits = 12 , corresponds to 2^12 = 2096 subnets.
Host Bits = 4 , corresponds to (2^4-2) = 14 hosts.
4096 subnets and 14 hosts.

Example 11:

How many subnets and hosts per subnet can you get from the network 172.22.0.0 255.255.255.224?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.252.0 = /27
                  = 255. 255. 11111111. 11100000
Subnet Bits = 11 , corresponds to 2^11 = 2048 subnets.
Host Bits = 5 , corresponds to (2^5-2) = 30 hosts.
2048 subnets and 30 hosts.

Example 12:

How many subnets and hosts per subnet can you get from the network 172.23.0.0 255.255.255.128?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.255.128 = /25
                  = 255. 255. 11111111. 10000000
Subnet Bits = 9 , corresponds to 2^9 = 512 subnets.
Host Bits = 7 , corresponds to (2^7-2) = 126 hosts.

512 subnets and 126 hosts.

Example 13:

How many subnets and hosts per subnet can you get from the network 172.24.0.0/24?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.255.0 = /24
                  = 255. 255. 11111111. 00000000
Subnet Bits = 8 , corresponds to 2^8 = 256 subnets.
Host Bits = 8 , corresponds to (2^8-2) = 254 hosts.
256 subnets and 254 hosts.

Example 14:

How many subnets and hosts per subnet can you get from the network 172.25.0.0/22?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.252.0 = /22
                  = 255. 255. 11111100. 00000000
Subnet Bits = 6 , corresponds to 2^6 = 64 subnets.
Host Bits = 10 , corresponds to (2^10-2) = 1022 hosts.
64 subnets and 1022 hosts.

Example 15:

How many subnets and hosts per subnet can you get from the network 172.25.0.0 255.255.255.0?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.255.0 = /24
                  = 255. 255. 11111111. 00000000
Subnet Bits = 8 , corresponds to 2^8 = 256 subnets.
Host Bits = 8 , corresponds to (2^8-2) = 254 hosts.
256 subnets and 254 hosts.

Example 16:

How many subnets and hosts per subnet can you get from the network 172.26.0.0 255.255.255.128?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.255.128 = /25
                  = 255. 255. 11111111. 10000000
Subnet Bits = 9 , corresponds to 2^9 = 512 subnets.
Host Bits = 7 , corresponds to (2^7-2) = 126 hosts.
512 subnets and 126 hosts.

Example 17:

How many subnets and hosts per subnet can you get from the network 172.26.0.0 255.255.248.0?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.248.0 = /21
                  = 255. 255. 11111000. 00000000
Subnet Bits = 5 , corresponds to 2^5 = 32 subnets.
Host Bits = 11 , corresponds to (2^11-2) = 2046 hosts.
32 subnets and 2046 hosts.

Example 18:

How many subnets and hosts per subnet can you get from the network 172.27.0.0/22?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.252.0 = /22
                  = 255. 255. 11111100. 00000000
Subnet Bits = 6 , corresponds to 2^6 = 64 subnets.
Host Bits = 10 , corresponds to (2^10-2) = 1022 hosts.
64 subnets and 1022 hosts.

Example 19:

How many subnets and hosts per subnet can you get from the network 172.28.0.0 255.255.254.0?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.254.0 = /23
= 255. 255. 11111110. 00000000
Subnet Bits = 7 , corresponds to (2^7-2) = 126 subnets.
Host Bits = 9 , corresponds to (2^9-2) = 510 hosts.
126 subnets and 510 hosts.

Example 20:

How many subnets and hosts per subnet can you get from the network 172.29.0.0 255.255.252.0?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.252.0 = /22
                  = 255. 255. 11111100. 00000000
Subnet Bits = 6 , corresponds to 2^6 = 64 subnets.
Host Bits = 10 , corresponds to (2^10-2) = 1022 hosts.
64 subnets and 1022 hosts.

Example 21:

How many subnets and hosts per subnet can you get from the network 172.30.0.0/20?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.240.0 = /20
                  = 255. 255. 11110000. 00000000
Subnet Bits = 4 , corresponds to 2^4 = 16 subnets.
Host Bits = 12 , corresponds to (2^12-2) = 4094 hosts.
16 subnets and 4094 hosts.

Example 22:

How many subnets and hosts per subnet can you get from the network 172.31.0.0/24?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.255.0 = /24
                  = 255. 255. 11111111. 00000000
Subnet Bits = 8 , corresponds to 2^8 = 256 subnets.
Host Bits = 8 , corresponds to (2^8-2) = 254 hosts.
256 subnets and 254 hosts.

Example 23:

How many subnets and hosts per subnet can you get from the network 172.31.0.0/28?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.255.240 = /28
                  = 255. 255. 11111111. 11110000
Subnet Bits = 12 , corresponds to 2^12 = 4096 subnets.
Host Bits = 4 , corresponds to (2^4-2) = 14 hosts.
4096 subnets and 14 hosts.

Example 24:

How many subnets and hosts per subnet can you get from the network 172.31.0.0/26?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.255.192 = /26
                  = 255. 255. 11111111. 11000000
Subnet Bits = 10 , corresponds to 2^10 = 1024 subnets.
Host Bits = 6 , corresponds to (2^8-2) = 62 hosts.
1024 subnets and 62 hosts.

Example 25:

How many subnets and hosts per subnet can you get from the network 172.31.0.0 255.255.254.0?

Solution:

Class B addresses use a default mask of 255.255.0.0
Given subnet mask = 255.255.254.0 = /23
                  = 255. 255. 11111110. 00000000
Subnet Bits = 7, corresponds to 2^7 = 128 subnets.
Host Bits = 9, corresponds to (2^9-2) = 510 hosts.
128 subnets and 510 hosts.

Class C

Example 26:

How many subnets and hosts per subnet can you get from the network 192.168.231.0/25?

Solution:

Class C addresses use a default mask of 255.255.255.0
Given subnet mask = 255.255.255.128 = /25
                  = 255. 255. 255. 10000000
Subnet Bits =1 , corresponds to 2^1 = 2 subnets.
Host Bits = 7 , corresponds to (2^7-2) = 126 hosts.
2 subnets and 126 hosts.

Example 27:

How many subnets and hosts per subnet can you get from the network 192.168.72.0/25?

Solution:

Class C addresses use a default mask of 255.255.255.0
Given subnet mask = 255.255.255.128 = /25
                  = 255. 255.255. 10000000
Subnet Bits =1 , corresponds to 2^1 = 2 subnets.
Host Bits = 7 , corresponds to (2^7-2) = 126 hosts.
2 subnets and 126 hosts.

Example 28:

How many subnets and hosts per subnet can you get from the network 192.168.62.0 255.255.255.192?

Solution:

Class C addresses use a default mask of 255.255.255.0
Given subnet mask = 255.255.255.192 = /26
                  = 255. 255. 255. 11000000
Subnet Bits =2 , corresponds to 2^2 = 4 subnets.
Host Bits = 6 , corresponds to (2^6-2) = 62 hosts.
4 subnets and 62 hosts.

Example 29:

How many subnets and hosts per subnet can you get from the network 192.168.21.0 255.255.255.192?

Solution:

Class C addresses use a default mask of 255.255.255.0
Given subnet mask = 255.255.255.192 = /26
                  = 255. 255. 255. 11000000
Subnet Bits =2 , corresponds to (2^2) = 4 subnets.
Host Bits = 6 , corresponds to (2^6-2) = 62 hosts.
4 subnets and 62 hosts.

Example 30:

How many subnets and hosts per subnet can you get from the network 192.168.95.0 255.255.255.192?

Solution:

Class C addresses use a default mask of 255.255.255.0
Given subnet mask = 255.255.255.192 = /26
                  = 255. 255. 255. 11000000
Subnet Bits =2 , corresponds to (2^2) = 4 subnets.
Host Bits = 6 , corresponds to (2^6-2) = 62 hosts.
4 subnets and 62 hosts.

Example 31:

How many subnets and hosts per subnet can you get from the network 192.168.51.0/27?

Solution:

Class C addresses use a default mask of 255.255.255.0
Given subnet mask = 255.255.255.224 = /27
                  = 255. 255. 255. 11100000
Subnet Bits = 3 , corresponds to (2^3) = 8 subnets.
Host Bits = 5 , corresponds to (2^5-2) = 30 hosts.
6 subnets and 30 hosts.

Example 32:

How many subnets and hosts per subnet can you get from the network 192.168.107.0 255.255.255.240?

Solution:

Class C addresses use a default mask of 255.255.255.0
Given subnet mask = 255.255.255.240 = /28
                  = 255. 255. 255. 11110000
Subnet Bits =4 , corresponds to (2^4) = 16 subnets.
Host Bits = 4 , corresponds to (2^4-2) = 14 hosts.
16 subnets and 14 hosts.

Example 33:

How many subnets and hosts per subnet can you get from the network 192.168.107.0 255.255.255.240?

Solution:

Class C addresses use a default mask of 255.255.255.0
  Given subnet mask = 255.255.255.248 = /29
                    = 255. 255. 255. 11111000
  Subnet Bits = 5 , corresponds to (2^5) = 32 subnets.
  Host Bits = 3 , corresponds to (2^3-2) = 6 hosts.
  32 subnets and 6 hosts.

Example 34:

How many subnets and hosts per subnet can you get from the network 192.168.219.0/29?

Solution:

Class C addresses use a default mask of 255.255.255.0
Given subnet mask = 255.255.255.248 = /29
                  = 255. 255. 255. 11111000
Subnet Bits = 5 , corresponds to (2^5) = 32 subnets.
Host Bits = 3 , corresponds to (2^3-2) = 6 hosts.
32 subnets and 6 hosts.

Exercise

Question 1:

What is the maximum number of subnets and hosts for the Class B address 156.100.0.0 with a subnet mask of 255.255.248.0?
A. 30 subnets ; 2046 hosts
B. 64 subnets ; 1022 hosts
C. 16 subnets ; 4094 hosts
D. 8 subnets ; 510 hosts

Answer:

Question 2:

You have an IP of 156.133.40.56 with a subnet mask of 7 bits. How many hosts and subnets are possible?
A. 126 hosts and 510 subnets
B. 128 subnets and 512 hosts
C. 510 hosts and 126 subnets
D. 512 subnets and 128 hosts

Answer:

Question 3:

The network address of 172.16.0.0/19 provides how many subnets and hosts?
A. 7 subnets, 30 hosts
B. 6 subnets, 8,190 hosts
C. 7 subnets, 8,190 hosts
D. 8 subnets, 30 hosts
E. 8 subnets, 2,046 hosts

Answer:

Question 4:

You are given a Class C network with 25 bits of networking. How many subnets do you have?

Answer:

Subnet Tutorials

Adscend

4.9.13

Only Number Of Host

Only Number Of Host

Class B

Class c

Calculating Number of Hosts And Subnets
Class B

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Adscend

4.9.13

Only Number Of Host

Only Number Of Host

Class B

Class c

Calculating Number of Hosts And SubnetsClass B

No comments:

Post a Comment

Calculating Number of Hosts And Subnets
Class B