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Showing posts with label Broadcast Valid Host Range Class C. Show all posts
Showing posts with label Broadcast Valid Host Range Class C. Show all posts

5.9.13

Broadcast Valid Host Range Class B

Subnet, Broadcast, Valid Host Range:Class B




Example: 1
Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.128.0(/17).

Example: 2
Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.192.0(/18).

Example: 3
Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.240.0(/20).

Example: 4
Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.248.0(/21).

Example: 5
Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.254.0(/23).

Example: 6
Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.255.0(/24).

Example: 7
Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.255.128(/25).

Example: 8
Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.255.192(/26).

Example: 9
Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.5 255.255.255.128(/25).

Example: 10
Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.13 255.255.255.252.

Example: 11
Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.17 255.255.255.252(/30).

Example: 12
Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.66 255.255.255.224(/27).

Example: 13
Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.90 255.255.255.192.

Example: 14
Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.33 255.255.255.224(/27).

Example: 15
Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.33 255.255.255.240(/28).

Example: 16
Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.33 255.255.255.248.

Example: 17
Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.65 255.255.255.192(/26).


Example 1: Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.128.0(/17).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.128.0
                  = 255. 255. 10000000. 00000000
Subnets = 2^1 = 2.
Hosts = 2^15 – 2 = 32766.
Block Size = 2^7 = 128.
Valid subnets = 256 – 128 = 128, means we have a
block size of 128 in the third octet.
Subnets are 0, 128.
Address 16 falls in the 0 subnet.
Subnet = 172. 16. 0. 0
The subnets would be 172.16.0.0, 172.16.128.0.
 
Network Assignable Host Broadcast
172.16.0.0 172.16.0.1-172.16.127.254 172.16.127.255
172.16.8.0 172.16.128.1-172.16.255.254 172.16.255.255
The subnet is: 172.16.0.0.
The broadcast address is:172.16.127.255.
The valid host range: 172.16.0.1-172.16.127.254.

Example 2: Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.192.0(/18).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.192.0(/19)
                  = 255. 255. 11000000. 00000000
Subnets = 2^2 = 4.
Hosts = 2^14 – 2 = 16382.
Block Size = 2^6 = 64.
Valid subnets = 256 – 192 = 64, means we have a
block size of 64 in the third octet.
Subnets are 0, 64, 128, 192.
Address 16 falls in the 0 subnet.
Subnet = 172. 16. 0. 0
The subnets would be 172.16.0.0, 172.16.64.0, 172.16.128.0,
172.16.192.0.
 
Network Assignable Host Broadcast
172.16.0.0 172.16.0.1-172.16.63.254 172.16.63.255
172.16.64.0 172.16.64.1-172.16.127.254 172.16.127.255
172.16.128.0 172.16.128.1-172.16.191.254 172.16.191.255
172.16.192.0 172.16.192.1-172.16.255.254 172.16.255.255
The subnet is: 172.16.0.0.
The broadcast address is:172.16.63.255.
The valid host range: 172.16.0.1-172.16.63.254.

Example 3: Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.240.0(/20).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.240.0
                  = 255. 255. 11110000. 00000000
Subnets = 2^4 = 16.
Hosts = 2^12 – 2 = 4094.
Block Size = 2^4 = 16.
Valid subnets = 256 – 240 = 16, means we have a
block size of 16 in the third octet.
Subnets are 0, 16, 32, 48, … , 240.
Address 16 falls in the 0 subnet.
Subnet = 172. 16. 0. 0
The subnets would be 172.16.0.0, 172.16.16.0, 172.16.32.0,
172.16.48.0, … , 172.16.240.0.
 
Network Assignable Host Broadcast
172.16.0.0 172.16.0.1-172.16.15.254 172.16.15.255
172.16.16.0 172.16.16.1-172.16.31.254 172.16.31.255
172.16.32.0 172.16.32.1-172.16.47.254 172.16.47.255
172.16.48.0 172.16.48.1-172.16.63.254 172.16.63.255
.
.
172.16.240.0 172.16.240.1-172.16.254.255 172.16.255.255
The subnet is: 172.16.0.0.
The broadcast address is: 172.16.15.255.
The valid host range: 172.16.0.1-172.16.15.254.

Example 4: Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.248.0(/21).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.248.0
                  = 255. 255. 11111000. 00000000
Subnets = 2^5 = 32.
Hosts = 2^11 – 2 = 2048.
Block Size = 2^3 = 8.
Valid subnets = 256 – 248 = 8, means we have a
block size of 8 in the third octet.
Subnets are 0, 8, 16,24, … , 248.
Address 16 falls in the 0 subnet.
Subnet = 172. 16. 0. 0
The subnets would be 172.16.0.0, 172.16.8.0, 172.16.16.0,
172.16.24.0, … , 172.16.248.0.
 
Network Assignable Host Broadcast
172.16.0.0 172.16.0.1-172.16.7.254 172.16.7.255
172.16.8.0 172.16.8.1-172.16.15.254 172.16.15.255
172.16.16.0 172.16.16.1-172.16.23.254 172.16.23.255
172.16.24.0 172.16.24.1-172.16.31.254 172.16.31.255
.
.
.
172.16.240.0 172.16.240.1-172.16.247.254 172.16.247.255
172.16.248.0 172.16.248.1-172.16.255.254 172.16.255.255
The subnet is: 172.16.0.0.
The broadcast address is: 172.16.7.255.
The valid host range: 172.16.0.1-172.16.7.254.

Example 5: Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.254.0(/23).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.254.0
                  = 255. 255. 11111110. 00000000
Subnets = 2^7 = 128.
Hosts = 2^9 – 2 = 510.
Block Size = 2^1 = 2.
Valid subnets = 256 – 254 = 2, means we have a
block size of 2 in the third octet.
Subnets are 0, 2, 4, 6, … , 254.
Address 16 falls in the 0 subnet.
Subnet = 172. 16. 0. 0
The subnets would be 172.16.0.0, 172.16.2.0, 172.16.4.0,
172.16.6.0, … , 172.16.254.0.
 
Network Assignable Host Broadcast
172.16.0.0 172.16.0.1-172.16.1.254 172.16.1.255
172.16.2.0 172.16.2.1-172.16.3.254 172.16.3.255
172.16.4.0 172.16.4.1-172.16.5.254 172.16.5.255
172.16.6.0 172.16.6.1-172.16.7.254 172.16.7.255
.
.
172.16.254.0 172.16.254.1-172.16.255.254 172.16.255.255
The subnet is: 172.16.0.0.
The broadcast address is: 172.16.1.255.
The valid host range: 172.16.0.1-172.16.1.254.

Example 6: Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.255.0(/24).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.0
                  = 255. 255. 11111111. 00000000
Subnets = 2^8 = 256.
Hosts = 2^8 – 2 = 254.
Block Size = 2^0 = 1.
Valid subnets = 256 – 255 = 1, means we have a
block size of 1 in the third octet.
Subnets are 0, 1, 2, 3, … , 255.
Address 16 falls in the 0 subnet.
Subnet = 172. 16. 0. 0
The subnets would be 172.16.0.0, 172.16.1.0, 172.16.2.0,
172.16.3.0, … , 172.16.255.0.
 
Network Assignable Host Broadcast
172.16.0.0 172.16.0.1-172.16.0.254 172.16.0.255
172.16.1.0 172.16.1.1-172.16.1.254 172.16.1.255
172.16.2.0 172.16.2.1-172.16.2.254 172.16.2.255
172.16.3.0 172.16.3.1-172.16.3.254 172.16.3.255
. . .
172.16.254.0 172.16.254.1-172.16.253.254 172.16.253.255
172.16.255.0 172.16.255.1-172.16.254.254 172.16.254.255
The subnet is: 172.16.0.0.
The broadcast address is: 172.16.0.255.
The valid host range: 172.16.0.1-172.16.0.254.

Example 7: Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.255.128(/25).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.128
                  = 255. 255. 11111111. 10000000
Subnets = 2^9 = 512.
Hosts = 2^7 – 2 = 126.
Block Size = 2^7 = 128.
Valid subnets = 256 – 128 = 128, means we have a block size of
128 in the forth octet.
Subnets are 0, 128.
Address 16 falls in the 0 subnet.
Subnet = 172. 16. 0. 0
The subnets would be 172.16.0.0, 172.16.0.128.
 
Network Assignable Host Broadcast
172.16.0.0 172.16.0.1-172.16.0.126 172.16.0.127
172.16.0.128 172.16.0.129-172.16.0.254 172.16.0.255
The subnet is: 172.16.0.0.
The broadcast address is: 172.16.0.127.
The valid host range: 172.16.0.1-172.16.0.126.

Example 8: Calculate Subnet, Broadcast, Valid Host Range of 172.16.0.0 255.255.255.192(/26).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.192
                  = 255. 255. 11111111. 11000000
Subnets = 2^10 = 1024.
Hosts = 2^6 – 2 = 62.
Block Size = 2^6 = 64.
Valid subnets = 256 – 192 = 64, means we have a block size of
64 in the forth octet.
Subnets are 0, 64, 128, 192.
Address 16 falls in the 0 subnet.
Subnet = 172. 16. 0. 0
The subnets would be 172.16.0.0, 172.16.0.64, 172.16.0.128,
172.16.0.192.
 
Network Assignable Host Broadcast
172.16.0.0 172.16.0.1-172.16.0.62 172.16.0.63
172.16.0.64 172.16.0.65-172.16.0.126 172.16.0.127
172.16.0.128 172.16.0.129-172.16.0.190 172.16.0.191
172.16.0.192 172.16.0.193-172.16.0.254 172.16.0.255
The subnet is: 172.16.0.0.
The broadcast address is: 172.16.0.63.
The valid host range: 172.16.0.1-172.16.0.62.

Example 9: Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.5 255.255.255.128(/25).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.128(/25)
                  = 255. 255. 11111111. 10000000
10.5    = 00001010. 00000101
255.128 = 11111111. 10000000
------------------------------
    And = 00001010. 00000000 = 10.0
Subnet = 172. 16. 10. 0
Subnets = 2^9 = 512.
Hosts = 2^7 – 2 = 126.
Block Size = 2^7 = 128.
Valid subnets = 256 – 128 = 128, means we have a block size of
128 in the forth octet.
Subnets are 0, 128.
Address 5 falls in the 0 subnet.
Subnet = 172. 16. 10. 0
The subnets would be 172.16.10.0, 172.16.10.128.
Network Assignable Host Broadcast
172.16.10.0 172.16.10.1-172.16.10.126 172.16.10.127
172.16.10.128 172.16.10.129-172.16.10.245 172.16.10.255
The subnet is: 172.16.10.0.
The broadcast address is:172.16.10.127.
The valid host range: 172.16.10.1-172.16.10.126.

Example 10: Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.13 255.255.255.252.
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.252
                  = 255. 255. 11111111. 11111100

Subnets = 2^14 = 16384.
Hosts = 2^2 – 2 = 2.
Block Size = 2^5 = 32.
Valid subnets = 256 – 252 = 4, means we have a block size of
4 in the forth octet.
Subnets are 0, 4, 8, 12, 16,… , 252.
Address 13 falls in the 12 subnet.
Subnet = 172. 16. 10. 12
The subnets would be 172.16.10.0, 172.16.10.4, 172.16.10.8,
172.16.10.12, 172.16.10.16 … , 172.16.10.252.
Network Assignable Host Broadcast
172.16.10.0 172.16.10.1-172.16.10.2 172.16.10.3
172.16.10.4 172.16.10.5-172.16.10.6 172.16.10.7
172.16.10.8 172.16.10.9-172.16.10.10 172.16.10.11
172.16.10.12 172.16.10.13-172.16.10.14 172.16.10.15
172.16.10.16 172.16.10.17-172.16.10.18 172.16.10.19
.
172.16.10.252 172.16.10.253-172.16.10.254 172.16.10.255
The subnet is: 172.16.10.12.
The broadcast address is:172.16.10.15.
The valid host range: 172.16.10.13-172.16.10.14.

Example 11: Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.17 255.255.255.252(/30).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.252(/30)
                  = 255. 255. 11111111. 11111100
    172.16.10.17  = 10101100. 00010000. 00001010. 00011110
255.255.255.252   = 11111111. 11111111. 11111111. 11110000
-----------------------------------------------------------
              And = 10101100. 00010000. 00001010. 00010000
                  = 172. 16. 10. 16 = Subnet
Subnets = 2^14 = 16384.
Hosts = 2^2 – 2 = 2.
Block Size = 2^2 = 4.
Valid subnets = 256 – 252 = 4, means we have a block size of 4
in the forth octet.
Subnets are 0, 4, 8, 12, 16, 20, … , 252.
Address 17 falls in the 16 subnet.
Subnet = 172. 16. 10. 16
The subnets would be 172.16.10.0, 172.16.10.4, 172.16.10.8,
172.16.10.12, 172.16.10.16, … , 172.16.10.252.
 
Network Assignable Host Broadcast
172.16.10.0 172.16.10.1-172.16.10.2 172.16.10.3
172.16.10.4 172.16.10.5-172.16.10.6 172.16.10.7
172.16.10.8 172.16.10.9-172.16.10.10 172.16.10.11
172.16.10.12 172.16.10.13-172.16.10.14 172.16.10.15
172.16.10.16 172.16.10.17-172.16.10.18 172.16.10.19
.
.
172.16.10.252 172.16.10.253-172.16.10.254 172.16.10.255
The subnet is: 172.16.10.16.
The broadcast address is:172.16.10.19.
The valid host range: 172.16.10.17-172.16.10.18.

Example 12: Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.66 255.255.255.224(/27).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.224(/27)
                  = 255. 255. 11111111. 11100000
Subnets = 2^3 = 8.
Hosts = 2^5 – 2 = 30.
Block Size = 2^5 = 32.
Valid subnets = 256 – 224 = 32, means we have a block size of
32 in the forth octet.
Subnets are 0, 32, 64, 96, … , 224.
Address 66 falls in the 64 subnet.
Subnet = 172. 16. 10. 64
The subnets would be 172.16.10.0, 172.16.10.32, 172.16.10.64,
172.16.10.96, … , 172.16.10.224.
Network Assignable Host Broadcast
172.16.10.0 172.16.10.1-172.16.10.30 172.16.10.31
172.16.10.32 172.16.10.33-172.16.10.62 172.16.10.63
172.16.10.64 172.16.10.65-172.16.10.94 172.16.10.95
172.16.10.96 172.16.10.97-172.16.10.126 172.16.10.127
.
.
172.16.10.224 172.16.10.225-172.16.10.254 172.16.10.255
The subnet is: 172.16.10.64.
The broadcast address is:172.16.10.95.
The valid host range: 172.16.10.65-172.16.10.94.

Example 13: Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.90 255.255.255.192.
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.192
                  = 255. 255. 11111111. 11000000
Subnets = 2^2 = 4.
Hosts = 2^6 – 2 = 62.
Block Size = 2^6 = 64.
Valid subnets = 256 – 192 = 64, means we have a block size of
64 in the forth octet.
Subnets are 0, 64, 128, 192.
Address 90 falls in the 64 subnet.
Subnet = 172. 16. 10. 64
The subnets would be 172.16.10.0, 172.16.10.64, 172.16.10.128,
172.16.10.192.
 
Network Assignable Host Broadcast
172.16.10.0 172.16.10.1-172.16.10.62 172.16.10.63
172.16.10.64 172.16.10.65-172.16.10.126 172.16.10.127
172.16.10.128 172.16.10.129-172.16.10.190 172.16.10.191
172.16.10.192 172.16.10.193-172.16.10.254 172.16.10.255
The subnet is: 172.16.10.64.
The broadcast address is:172.16.10.127.
The valid host range: 172.16.10.65-172.16.10.126.

Example 14: Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.33 255.255.255.224(/27).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.224(/27)
                  = 255. 255. 11111111. 11100000
Subnets = 2^11 = 2048.
Hosts = 2^5 – 2 = 30.
Block Size = 2^5 = 32.
Valid subnets = 256 – 224 = 32, means we have a block size of
32 in the forth octet.
Subnets are 0, 32, 64, 96, … , 224.
Address 33 falls in the 32 subnet.
Subnet = 172. 16. 10. 32
The subnets would be 172.16.10.0, 172.16.10.32, 172.16.10.64,
172.16.10.96, … , 172.16.10.224.
 
Network Assignable Host Broadcast
172.16.10.0 172.16.10.1-172.16.10.30 172.16.10.31
172.16.10.32 172.16.10.33-172.16.10.62 172.16.10.63
172.16.10.64 172.16.10.65-172.16.10.94 172.16.10.95
172.16.10.96 172.16.10.97-172.16.10.126 172.16.10.127
.
.
172.16.10.224 172.16.10.225-172.16.10.254 172.16.10.255
The subnet is: 172.16.10.32.
The broadcast address is:172.16.10.63.
The valid host range: 172.16.10.33-172.16.10.62.

Example 15: Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.33 255.255.255.240(/28).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.240(/28)
                  = 255. 255. 11111111. 11110000
Subnets = 2^12 = 4096.
Hosts = 2^4 – 2 = 14.
Block Size = 2^4 = 16.
Valid subnets = 256 – 240 = 16, means we have a block size of
16 in the forth octet.
Subnets are 0, 16, 32, 48, … , 240.
Address 33 falls in the 32 subnet.
Subnet = 172. 16. 10. 32
The subnets would be 172.16.10.0, 172.16.10.16, 172.16.10.32,
172.16.10.48, … , 172.16.10.240.
 
Network Assignable Host Broadcast
172.16.10.0 172.16.10.1-172.16.10.14 172.16.10.15
172.16.10.16 172.16.10.17-172.16.10.30 172.16.10.31
172.16.10.32 172.16.10.33-172.16.10.46 172.16.10.47
172.16.10.48 172.16.10.49-172.16.10.62 172.16.10.63
.
.
172.16.10.240 172.16.10.241-172.16.10.254 172.16.10.255
The subnet is: 172.16.10.32.
The broadcast address is:172.16.10.47.
The valid host range: 172.16.10.33-172.16.10.46.

Example 16: Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.33 255.255.255.248.
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.248
                  = 255. 255. 11111111. 11111000
Subnets = 2^13 = 8192.
Hosts = 2^3 – 2 = 6.
Block Size = 2^3 = 8.
Valid subnets = 256 – 248 = 8, means we have a block size of
8 in the forth octet.
Subnets are 0, 8, 16, 24, 32, 40, … , 248.
Address 33 falls in the 32 subnet.
Subnet = 172. 16. 10. 32
The subnets would be 172.16.10.0, 172.16.10.8, 172.16.10.16,
172.16.10.24, 172.16.10.32, 172.16.10.40, … , 172.16.10.248.
 
Network Assignable Host Broadcast
172.16.10.0 172.16.10.1-172.16.10.6 172.16.10.7
172.16.10.8 172.16.10.9-172.16.10.14 172.16.10.15
172.16.10.16 172.16.10.17-172.16.10.22 172.16.10.23
172.16.10.24 172.16.10.25-172.16.10.31 172.16.10.32
172.16.10.32 172.16.10.33-172.16.10.38 172.16.10.39
.
172.16.10.248 172.16.10.249-172.16.10.254 172.16.10.255
The subnet is: 172.16.10.32.
The broadcast address is: 172.16.10.39.
The valid host range: 172.16.10.33-172.16.10.38.

Example 17: Calculate Subnet, Broadcast, Valid Host Range of 172.16.10.65 255.255.255.192(/26).
Solution
Class B addresses use a default mask of 255.255.0.0.
Given subnet mask = 255.255.255.192(/26)
                  = 255. 255. 11111111. 11000000
Subnets = 2^10 = 1024.
Hosts = 2^6 – 2 = 62.
Block Size = 2^6 = 64.
Valid subnets = 256 – 192 = 64, means we have a block size of
64 in the forth octet.
Subnets are 0, 64, 128, 192.
Address 65 falls in the 64 subnet.
Subnet = 172. 16. 10. 64
The subnets would be 172.16.10.0, 172.16.10.64, 172.16.10.128,
172.16.10.192.
 
Network Assignable Host Broadcast
172.16.10.0 172.16.10.1-172.16.10.62 172.16.10.63
172.16.10.64 172.16.10.65-172.16.10.126 172.16.10.127
172.16.10.128 172.16.10.129-172.16.10.190 172.16.10.191
172.16.10.192 172.16.10.193-172.16.10.254 172.16.10.255
The subnet is: 172.16.10.64.
The broadcast address is:172.16.10.127.
The valid host range: 172.16.10.65-172.16.10.126.